How many moles of aluminum bromide would be produced from reacting 20.0 grams of aluminum with excess bromine?
20.0 g Al X 1 mole Al X 2 mole AlBr3 X 266.7 g AlBr3 = 132 g AlBr3
27 g Al 3 mole Al 1 mole Al

"hydrogen bonding is the attraction of h atoms in the water molecule (slight + charge) to o atoms in a neighboring water molecule (slight - charge); it is a weak interatomic force. but it is still strong enough to the water molecules "stick" together."

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explanation: