A solution with a pOH of 4.3 has a [H+] of ??
please help

A solution with a pOH of 4.3 has a [H+] of 2*10⁻¹⁰ M.

Explanation:

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.

pOH indicates the concentration of hydroxyl ions [OH-] present in a solution. It is defined as the negative logarithm of the activity of hydroxide ions. That is, the concentration of OH- ions:

pOH= -log [OH-]

On the other hand, pH is also a measure of the basicity or alkalinity of a solution. POH is an indicator that is related to pH by:

pOH + pH= 14

So, if the solution has a pOH equal to 4.3, the pH is calculated by:

4.3 + pH= 14

pH= 14 - 4.3

pH= 9.7

The pH is defined as the logarithm of the concentration of H+ ions, with the sign changed:

pH= -log [H+]

So, in this case:

9.7= - log[H+]

Solving

[H+]= 2*10⁻¹⁰ M

A solution with a pOH of 4.3 has a [H+] of 2*10⁻¹⁰ M.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml