What is the mole fraction of ethanol (C2H5OH) in a solution of 47.5 g of ethanol in 850 g of water?

Unless I've completely forgotten my chemistry, mole fraction is the fraction of moles of a particular solute of the entire number of moles in the solution. So for this question: formula weight of ethanol = 46.07 g/mol formula weight of water = 18.015 g/mol moles of ethanol = 47.5g / 46.07 g/mol = 1.0310 mol moles of water = 850g / 18.015 g/mol = 47.182 mol total number of moles in the solution = 1.0310 + 47.182 = 48.213 mol therefore, the mole fraction of ethanol is 1.0310 mol / 48.213 mol = 0.0214 hope this helps.

0.021

Explanation:

that's the answer because I just did an exam that included this question and then the miss explained to me why this was the answer, but don't worry am 100% sure the answer is 0.021 .