If I performed an experiment that resulted with a product mass of 15 g (experiemental value). However, based on my stoichiometric calculations (accepted value) I should have gotten a mass of 18 g. What is my percent yield?

some sources quote the lethal dose, for an average 170lbs opiate-naive individual is between 75 and 375 mg

what does the table look like

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o