The system we will be observing in this lab involves the cobalt(II) ion. This ion can form two complexes, one with water and one with the chloride
ion (CI'). Below is a reaction showing the addition of chloride ions to the
cobalt - water complex.
Co(H2016 + Cl <--> COC142- + H2O
2+
pink
blue
What happened when HCl was added?

See Explanation

Explanation:

In the equilibrium shown in the question,on the left hand side is a pink hexaaquacobalt II  complex which is pink in colour. On the right hand side, we have a tetrachlorocobalt II complex which is blue in colour.

The equilibrium can be shifted from left to right by adding HCl (a source of chloride ions).

Hence, when HCl is added to the system, the equilibrium position is shifted to the right thereby yielding the blue solution of the tetrachlorocobalt II complex.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i