During a laboratory experiment, 36.12 grams of Aboz was formed when O2 reacted with aluminum metal at 280.0 K and 1.4 atm. What was the volume of O2 used during the experiment?
30 2+ 4A1 -- 2AI2O3
8.70 liters
9.22 liters
10.13 liters
12.81 liters

8.70 liters

Explanation:

First we convert 36.12 g of AI₂O₃ into moles, using its molar mass:

Then we convert AI₂O₃ moles into O₂ moles, using the stoichiometric coefficients of the reaction:

We can now use the PV=nRT equation to calculate the volume, V:

particle   p is an electron and particle q is a neutron

the answer is b. dilution