Label the states of each compound in the reaction below. CuSO4( ) + 2KOHC ) + Cu(OH)2( ) + K2SO4( )

CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)

Explanation:

CuSO₄ + 2KOH —> Cu(OH)₂ + K₂SO₄

To know the state of each compounds, we shall determine the complete ionic equation. This can be obtained as follow:

In solution, CuSO₄ and KOH will dissociate as follow:

CuSO₄(aq) —> Cu²⁺(aq) + SO₄²¯(aq)

KOH (aq) —> K⁺ (aq) + OH¯(aq)

CuSO₄(aq) + KOH (aq) —>

Cu²⁺(aq) + SO₄²¯(aq) + 2K⁺(aq) + 2OH¯(aq) —> Cu(OH)₂(s) + 2K⁺(aq) + SO₄²¯(aq)

Note: Cu(OH)₂ is insoluble in water.

Therefore, the elemental equation is:

CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)

it is called acid bonding

the answer is either b or c