Help m A 280.0 sample of neon gas exerts a pressure of 660.0 mm Hg at 26.0°C. Assuming that the pressure remains constant, at what temperature in would the volume change to 440.0 ml?

469.9K

Explanation:

Using Charles's law equation:

V1/T1 = V2/T2

Where;

V1 = initial volume (ml)

V2 = final volume (ml)

T1 = initial temperature (K)

T2 = final temperature (K)

Based on the information provided:

V1 = 280.0ml

V2 = 440.0 ml

T1 = 26.0°C = 26 + 273 = 299K

T2 = ?

Using V1/T1 = V2/T2

280/299 = 440/T2

0.936 = 440/T2

T2 = 440 ÷ 0.936

T2 = 469.9K

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )