Can someone please help me complete the balance equation for this reaction?​

2K(s) + F₂(g) —> 2KF(s)

Explanation:

__K(_) + __F₂(g) —> __KF(_)

The above equation can be balance as follow:

K(s) + F₂(g) —> KF(s)

There are 2 atoms of F on the left side and 1 atom on the right side. It can be balance by writing 2 before KF as shown below:

K(s) + F₂(g) —> 2KF(s)

There are 2 atoms of K on the right side and 1 atom on the left side. It can be balance by writing 2 before K as shown below:

2K(s) + F₂(g) —> 2KF(s)

Now, the equation is balanced.

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.