Calculate mL (4 sf) of 0.7500 M sodium hydroxide required to neutralize 35.00 mL of 0.7500 M phosphoric acid. Please input number as whole number not scientific notation

105mL of 0.7500M of NaOH are required

Explanation:

Phosphoric acid, H₃PO₄, reacts with sodium hydroxide, NaOH, as follows:

H₃PO₄ + 3 NaOH → Na₃PO₄ + 3H₂O

Where 1 mole of phosphoric acid reacts with 3 moles of NaOH

To solve this question we must find, as first, the moles of H3PO4 that react. Using the chemical equation we can find the moles of NaOH required to neutralize this acid. And, with its concentration, we can find the volume oof NaOH required:

Moles H3PO4:

35.00mL = 0.03500L * (0.7500mol / L) = 0.2625 moles H3PO4

Moles NaOH:

0.2625 moles H3PO4 * (3mol NaOH / 1mol H3PO4) = 0.07875 moles NaOH

Volume NaOH:

0.07875 moles NaOH * (1L / 0.7500mol) = 0.105L =

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

the awnser is group 12