A piece of hot metal 120 °C is placed into a calorimeter that contains 40 ml of water at 22 °C After heat exchange is complete the temperature of water is 28 °C What is the mass of the metal? (Assume that no heat is lost to the surroundings). specific heat of metal: 0.126 °C specific heat of water: 4.184 J°C 121 density of water. 1 g ml

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied