What is the temperature of a 6.1 mole sample of He gas at 18.5 bar and volume of 115L? (Round answer to the hundredths place)

4202.1 K

Explanation:

From;

PV=nRT

P= pressure of the gas = 18.5 bar

V = volume of the gas = 115L

n= number of moles of the gas =  6.1 mole

T= temperature of the gas = ?

R = gas constant = 0.083 L⋅bar⋅K−1⋅mol−1

T = PV/nR

T = 18.5 * 115/6.1 * 0.083

T = 2127.5/0.5063

T= 4202.1 K

108

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