Q=(10.og) (-239778.c)(50-100)

Please show work

1.199 × 10^8 J

Explanation:

This question describes how to calculate amount of heat absorbed using the formula;

Q = m × c × ∆T

Where;

Q = amount of heat absorbed (J)

m = mass of substance = 10.0g

c = specific heat capacity = -239778 J/g°C

∆T = change in temperature = 50°C - 100°C

To solve this, we have:

Q = 10.0 × -239778 × -50

Q = 119,889,000

Q = 1.199 × 10^8 J

these nuts

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.