2KOH + H2SO4 → K2SO4 + 2H20 What mass of water would be produced if 19.6g of KOH were reacted?

19.6 × ( 1 mol KOH / 56 grams KOH )

= 0.35 mol KOH

0.35 mol KOH ×( 2 mol H2O / 2 mol KOH )

= 0.35 mol H20

0.35 mol H2O × ( 18 g H2O / 1 mol H2O )

= 6.3 grams H2O

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