Chemistry, 31.05.2021 15:50 shazanah95

Describe you would obtain a sample of lead via electrolysis

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Electrolysis is defined as the process by which electrolyte allows electric current to pass through it and is decomposed in the process.

Explanation:

Substances that allow the passage of electric current are known as conductors. Examples of conductors are metals, graphites. Metals are good conductors of electricity of which an example is LEAD.

Lead is a metal which can be extracted through the process of electrolysis. A substance in solution or liquid state like lead (II) bromide which allows electric current to pass through it and at the same time decompose by it is known as an ELECTROLYTE.

In the electrolysis of lead (II) bromide to obtain Lead,the electrolyte ionize into positive and negative ions. The positive ions migrate to the cathode and are known as captions. The negative ions migrate to the anode and are known as anions.

--> At the CATHODE: Pb2+ gains electrons and Lead is deposited

Pb2+(aq) + 2e > Pb(s)

--> At the anode: Br- gives up electrons and is liberated as bromine vapour.

2Br- (aq) > Br2(g) + 2e.

Answer from: Quest

Read the sentences below in 1962, i tried to enroll as the first black student at the university of mississippi. the governor of mississippi blocked my entrance which best describes the verbs used in the sentences? o they are past tense verbs, which are often used in narrative essays o they are past tense verbs, which are not often used in narrative essays. o they are future tense verbs, which are often used in narrative essays o they are future tense verbs, which are not often used in narrative essays.

Answer from: Quest

answer : (a) volume of the gas = 8.67 × $10^{-3}$ l

(b) second virial coefficient b = -1.21226 l/mole

solution : given, t = 300k

p = 20atm

z = 0.86

n = 8.2 mmoles = 8.2 × $10^{-3}$ moles

r = 0.082 l atm/k/mol

find, (a) volume of gas and (b) second virial coefficient b at 300k.

formula used : $z=\frac{pv}{nrt}$

and $z=1+\frac{b}{v}$

(a) $z=\frac{pv}{nrt}$

$v=\frac{znrt}{p}$

= $\frac{0.86\times 8.2\times[tex]10^{-3}$ \times 0.082\times 300}{20}[/tex]

= 8.67 × $10^{-3}$ l

(b) $z=1+\frac{b}{v}$

$b=(z-1)v$

= (0.00867-1) × 8.659

= - 8.5839 l/mole

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