What is the pOH of a solution of pH 3 acid? (Kw= 1.0 x 10-14)

pOH = 11

Explanation:

The pH is an unit of concentration widely used in chemistry to find the quality of a solution.

To solve this question we must, as first, find the [H+] using the pH:

[H+] = 10^-pH

[H+] = 10^-3

Now, using kw:

kw = 1.0x10-14 = [H+] [OH-]

1.0x10-14 = [10^-3] [OH-]

[OH-] = 1.0x10-11

pOH = -log [OH-]

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.