A 0.158 g sample of a compound containing the elements carbon, hydrogen, oxygen, and sulphur was burned completely, yielding 0.110 g CO2 and 0.0677 g H2O. In a separate experiment, all the sulphur in another 0.158 g sample was converted to 0.292 g of BaSO4. What is the empirical formula of the unknown compound

sry but any answer choices

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g