Qué volumen (en metros cúbicos) deberá tener un gas que se encuentra a 3.3 atm en un recipiente cilíndrico de radio de 2.8 m y altura 4.6 m para que la presión final sea de 1.9 atm.

Volumen = 65.199 metro cúbico

Explanation:

Tal como lo conocemos

P1V1 = P2 V2

Aquí

P1 = 1,9 atmósferas

V1 = (pi) * r ^ 2 * h

Sustituyendo los valores dados, obtenemos

V1 = 3.14 * 2.8 * 2.8 * 4.6 = 113.241 metros cúbicos

V2 = por determinar

P2 = 3.3 atmósferas

Sustituyendo los valores dados y derivados en la fórmula principal, obtenemos -

1.9 atm * 113.241 metros cúbicos = 3.3 atm * V2

V2 = 1.9 atm * 113.241 metros cúbicos / 3.3 atm

V2 = 65.199 metro cúbico

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms