Silver nitrate, AgNO3, reacts with ferric chloride, FeCl3, to give silver chloride, AgCl, and ferric nitrate, Fe(NO3)3. In a particular experiment, it was planned to mix a solution containing 25.0 g of AgNO3 with another solution containing 45.0 grams of FeCl3. Write the chemical equation for the reaction.​

Explanation:

From the given question,

The chemical equation is:

We are given that:

mass of = 45 g

number of moles of  = 45 g/162.2 g/mol

= 0.28 mol

mass of = 25g

number of moles of  = 25/169.87

= 0.147 mol

From the given equation 1 mole of is required to make 3 mole of  

0.28 mole of = 0.28 × 3 = 0.84 mol of  

Here  is the limiting reagent.

Thus,

3 mole of  = 3 moles of AgCl

0.147 mole of = 0.147 mole of AgCl produced.