container has 3 moles of gas with a volume of 60 liters and at a temperature of 250 K, Calculate the pressure inside the container in kPa

103.9 KPa

Explanation:

From the ideal gas equation;

PV=nRT

From the parameters given;

P= ?

T=250 K

V= 60L

n=3

R=0.082 atmLK-1mol-1

P= nRT/V

P= 3 × 0.082 × 250/60

P= 1.025 atm

1 atm=101325 pascals

1.025 atm = 1.025 atm × 101325 pascals/1atm

= 103.9 KPa

103.9kPa

Explanation:

To solve this question we must use the equation:

PV = nRT

P = nRT / V

Where P is pressure in atm

n are moles of the gas = 3mol

R is gas constant = 0.082atmL/molK

T is absolute temperature = 250K

V = 60L

P = 3mol*0.082atmL/molK*250K / 60L

P = 1.025atm

As 1atm = 101.325kPa

1.025atm * (101.325kPa / 1atm) = 103.9kPa

your answers are a,b,,e and f

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