container has 3 moles of gas with a volume of 60 liters and at a temperature of 250 K, Calculate the pressure inside the container in kPa

103.98 kpa

Explanation:

Pv= nRT

Where

P= pressure of the system=

n= number of moles= 3 moles

T= temperature= 250 K

Volume of the container= 60 liters

R= 0.0821L.atm/K.mol

Substitute the values

Pv= nRT

P= nRT/ V

= (3×0.0821×250)/60

= 1.026 Atm

1atm= 101325 Pascal

1.026 atm= X

= 103984 pasca

Convert to kilopascal

= 103984 pasca /1000

= 103.98 kpascal

the answer is c i believe