How many grams of aluminum is required to react with 75.0 ml of 2.50 M HCl?

63 g Al is required to react with 35 mL of 2.50 M hydrochloric acid

I'm sorry if it's wrong, I tried.

Explanation:

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.