calculate the volume occupied by 15 moles of a gas at 1.14 atm and 265K. A-286.3L B-321.6L C-247.4L D-304.5L

A- 286.3L

Explanation:

Using the ideal gas law equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information given in this question;

P = 1.14atm

V = ?

n = 15moles

T = 265K

Using PV = nRT

V = nRT ÷ P

V = (15 × 0.0821 × 265) ÷ (1.14)

V = 326.35 ÷ 1.14

V = 286.27 L

V = 286.3L

a

explanation:

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