A solution contains 2.38 g of magnesium chloride, MgCl, in 500 cm3 of solution What is the concentration of
chloride ions in g/dm3?​​

3.54g Cl-/dm³

Explanation:

To solve this question we must, as first, find the mass of chloride ions finding first, the moles of MgCl2. Then, we must convert the cm³ to dm³ (1cm³ = 0.001dm³).

Moles MgCl2 -Molar mass: 95.211g/mol-

2.38g * (1mol / 95.211g) = 0.0250 moles MgCl2

Moles Cl-:

0.0250 moles MgCl2 * (2mol Cl- / 1mol MgCl2) = 0.0500 moles Cl-

Mass Cl- -Molar mass: 35.45g/mol-:

0.0500 moles Cl- * (35.45g / mol) = 1.77g of chloride ions

dm³:

500cm³ * (0.001dm³ / 1cm³) = 0.500dm³

The concentration is:

1.77g of chloride ions / 0.500dm³ =

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer