What is the mole fraction of ethanol when 23.2 g of ethanol(C2H5OH) are mixed with 73.1 g of water(H2O)? (atomic mass of C= 12, H = 1, O = 16,)

0.111

Explanation:

Step 1: Calculate the moles corresponding to 23.2 g of ethanol

The molar mass of C₂H₅OH is 46 g/mol.

23.2 g × 1 mol/46 g = 0.504 mol

Step 2: Calculate the moles corresponding to 73.1 g of water

The molar mass of H₂O is 18 g/mol.

73.1 g × 1 mol/18 g = 4.06 mol

Step 3: Calculate the total number of moles

n = nC₂H₅OH + nH₂O = 0.504 mol + 4.06 mol = 4.56 mol

Step 4: Calculate the mole fraction of ethanol

We will use the following expression.

Χ(C₂H₅OH) = nC₂H₅OH / n

Χ(C₂H₅OH) = 0.504 mol / 4.56 mol = 0.111

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.