The specific heat capacity of water is 4.186 J/g °C Calculate the temperature change when 8000 J of heat is added to 3g of water.
Use the equation q=mcT

Explanation:

Energy (Q) J

Change of temperature (ΔT) °C

Mass (m) kg

Substance (optional) Custom ▾

Specific heat capacity (c) J/(kg·K)

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Solution given:

specific heat capacity of water [c]4.186 J/g °C

temperature[∆T]=?

mass[m]=3g

heat[Q]=8000J

we have

Q=mc∆T

8000=3*4.186*∆T

∆T=8000/12.558

∆T=637.04°C

the temperature change is 637.04°C.

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be