If 18.5 grams of CuCl2 react with 22.8 grams of NaNO3, what mass of NaCl can be formed? CuCl2 + NaNO3 → Cu(NO3)2 + NaCl

12.4 g NaCl
15.7 g NaCl
16.2 g NaCl
28.4 g NaCl

From above calculations, gives the limited amount of NaCl. So, 15.7 g of NaCl would form from given amounts of reactants.

Explanation:

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the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

the right answer is c i just did the question.