Na2CO3(aq) + CaCl2(aq) —> 2 NaCl(aq) + CaCO3(s) Calculate the volume (in mL) of 0.200 M CaCl2 needed to produce 2.00 g of CaCO3(s).

There is an excess of Na2CO3.

Molar mass of calcium carbonate = 100.09 g/mol

Volume of calcium chloride = _ mL

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