2 NaOH + H2SO4 2 H2O + Na2S04 a. How many grams of sodium sulfate will be formed if you start with 300 grams of sodium
hydroxide?

532.5 grams

Explanation:

The balanced chemical equation of this reaction is as follows:

2NaOH + H2SO4 → 2H2O + Na2S04

From the above balanced equation, it shows that 2 moles of sodium hydroxide (NaOH) produces 1 mole of sodium sulfate (Na2SO4).

Using mole = mass/molar mass to convert mass to mole

Molar mass of NaOH = 23 + 1 + 16 = 40g/mol

mole = 300/40

mole = 7.5moles of NaOH

Since 2 moles of sodium hydroxide (NaOH) produces 1 mole of sodium sulfate (Na2SO4).

Then, 7.5 moles of NaOH will produce 7.5/2 = 3.75moles of Na2SO4.

mole = mass/molar mass

Molar mass of Na2SO4 = 23(2) + 32 + 16(4)

= 46 + 32 + 64

= 142g/mol

Mass of Na2SO4 = 3.75 × 142

= 532.5g

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.