1.The reaction of iron(III) oxide (Fe2O3) and hydrogen (H2) is represented by the following unbalanced chemical equation. Fe2O3(s)  H2(g) → Fe(s)  H2O(l)
Determine the mass in grams of hydrogen gas needed to react completely with
33.5 g Fe2O3.
Step 1.
Step 2.
Step 3.
Step 4.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

it is stable as it is in group 0 which have full outer shells of electrons