Calculate the number of milliliters of 0.587 M NaOH required to precipitate all of the Fe3 ions in 197 mL of 0.654 M FeCl3 solution as Fe(OH)3. The equation for the reaction is: FeCl3(aq) 3NaOH(aq) Fe(OH)3(s) 3NaCl(aq)

The number of milliliters of 654 mL for 0.587 M NaOH required to precipitate all of the ions in 197 mL of 0.654 M solution as .

Explanation:

The reaction equation is as follows.

Therefore, moles of are calculated as follows.

Moles = Molarity of   Volume (in L)

= 0.654 M 0.197 L  

= 0.128 mol

Now, according to the given balanced equation 1 mole of reacts with 3 moles of NaOH(aq). Hence, moles of  reacted are calculated as follows.

3 0.128 mol = 0.384 moles of NaOH

As moles of NaOH present are as follows.

Moles of NaOH = Molarity of NaOH Volume (in L)

0.384 mol = 0.587 M Volume (in L)

Volume (in L) = 0.654 L (1 L = 1000 mL) = 654 mL

Thus, we can conclude that the number of milliliters of 654 mL for 0.587 M NaOH required to precipitate all of the ions in 197 mL of 0.654 M solution as .

a corroding iron, if that's one of your choices

chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances. these processes are called chemical reactions and, in general, are not reversible except by further chemical reactions. some reactions produce heat and are called exothermic reactions and others may require heat to enable the reaction to occur, which are called endothermic reactions. understanding chemical changes is a major part of the science of chemistry.