The value for the equilibrium constant for the reaction 2SO2(g)+O2(g) rightleftharpoons 2SO3(g) is 4.0*10^ 1 24 at 298K What would be the value for the equilibrium constant for the following reaction at the same temperature? 2SO3(g) rightleftharpoons2502(g)+O2(g)

The value for the equilibrium constant for the reaction at 298K .

What would be the value for the equilibrium constant for the following reaction at the same temperature?

Explanation:

The Kc value for the reverse reaction of the first reaction that is:

For the reverse reaction,

So, it is the inverse of the first Kc value.

Hence, the new Kc value is:

Answer is :

Kc=2.5*10^-25.

the answer is 0.8m.

by: nicholas