The chemical equation is Mg(s) + O2(g) → MgO(s) 1. Magnesium is the limiting reactant in this experiment. What is the theoretical yield of MgO for each trial?

2. what is the percent yield of MgO for the experiment for each trial?

3. what is the average percent yield of MgO for the two trials?

The magnesium will burn until consumed entirely. There is much more oxygen available in the atmosphere than needed to consume the magnesium. Thus the magnesium is the limiting reactant because it determines the amount of product formed.

Explanation:

Mg produces less amount of MgO than O2; therefore Mg is the limiting reagent. O2 produces more amount of MgO than Mg; therefore O2 is the excess reagent.

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