A 0.5 mol sample of N2 is in a 6L container at 2 atm. what is the temperature of the gas in K

300 K

General Formulas and Concepts:

Atomic Structure

Gas Laws

Ideal Gas Law: PV = nRT

Explanation:

Step 1: Define

Identify variables

[Given] n = 0.5 mol N₂

[Given] V = 6 L

[Given] P = 2 atm

[Given] R = 0.0821 L · atm · mol⁻¹ · K⁻¹

[Solve] T

Step 2: Solve for T

Step 3: Check

Follow sig fig rules and round. We are given 1 sig fig as our lowest.

292.326 K ≈ 300 K

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .

- lead + phosphoric acid = hydrogen + lead(ii) phosphate