What volume of the solution contains 0.25 mol of MgCl2, with 0.995 M MgCl2?

0.251 L

Explanation:

c (concentration) = n(moles)/v(volume in litres)

0.995 M = 0.25 mol / v

v = 0.25 mol / 0.995 M

v = 0.251 L

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.

answer: i dont know the answer but this might

explanation:

l