“A chemist was creating iodine chloride according to the following reaction: 2I2 + KIO3 + 6HCL —> 5ICl + KCl + 3H2O
What volume of 0.5 M hydrochloric acid would need to be addd to make 24.9g of ICl assuming the other reactants are in excess?”

How do i solve this i am completely lost

10.063g / 10.00 ml = 1.0063 g/ml which rounds off to 4 sig figs as: 1.006 g/ml

Ais stronge

  the volume of  0.220 m k2s    solution  required  to  completely  react with 175 ml  of 0.115m co(no3)2  calculate the moles  of co(no3)2 =  molarity x volume/1000175 x0.115/1000= 0.02  moleswrite  the reacting  equationk2s(aq)  +  co(no3)2  = 2 kno3(aq)  + cos(s)by  use  of mole ratio between k2s to co(no3)2 which  is  1: 1 the moles of k2s is therefore = 175  x0.115/1000= 0.02  molesvolume = moles/molarity=0.02/0.22=0.09  ml  of k2s