How many liters of hydrogen gas are required to react with 3.5" liters of oxygen gas in the following reaction? 2H2(g)+O2(g) -->2H2O(g)

7 L of H₂.

Explanation:

The balanced equation for the reaction is given below:

2H₂ + O₂ —> 2H₂O

From the balanced equation above,

1 L of O₂ required 2 L of H₂.

Finally, we shall determine the volume of H₂ required to react with 3.5 L of O₂. This can be obtained as follow:

From the balanced equation above,

1 L of O₂ required 2 L of H₂.

Therefore, 3.5 L of O₂ will require

= 3.5 × 2 = 7 L of H₂.

Thus, 7 L of H₂ is required to for the reaction.

elements

explanation:

yes the other ones are right just show me a pic of ur face cuz u look hot

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6