Calculate the total amount of energy required in calories to convert 50.0 g of ice at 0.00 degrees Celsius to steam at 100. degrees Celsius. Specific heat capacity of water is 1.00 cal/g OC

Hfusion = 80 cal/g OC and Hvap = 540 cal/g OC

Write the complete equation you will use.

Substitute the values in the equation in step 1.

Report the math answer with 3 sig figs and the correct unit.

The amount of heat absorbed is

Explanation:

Few processes involved are:

(1):

(2):

(3):

Calculating the heat absorbed for the process having same temperature:

......(i)

where,

q is the amount of heat absorbed, m is the mass of sample and is the enthalpy of fusion or vaporization

Calculating the heat released for the process having different temperature:

......(ii)

where,

= specific heat of solid or liquid

are final and initial temperatures respectively

We are given:

Putting values in equation (i), we get:

We are given:

Putting values in equation (i), we get:

We are given:

Putting values in equation (i), we get:

Calculating the total amount of heat released:

Hence, the amount of heat absorbed is

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

what is the average time it took the car to travel 0.25 meters?

⇒ 2.23 seconds

what is the average time it took the car to travel 0.50 meters?

⇒ 3.13 seconds