A sample of O2 gas is put into a bottle at STP. If the volume of the bottle is 0.52 L, how many moles of O2 will the bottle contain? please help!!

Explanation:

So,at STP or NTP, one mole of any gas occupies 22.4 litres of volume. To find mass,firstly we have to calculate the no. Of moles present in 11.2 litres of O2 gas which can be calculated as ;

No. Of moles = Given Volume ÷ 22.4 Litre (provided that gas is at STP)

= 11.2 Litre / 22.4 Litre

= 0.5 moles

Now, mass can be calculated by;

Mass = no. Of moles × Molecular mass

= 0.5 × 32 (Molecular mass of O2 is 32u or 32 g, if you are calculating in Grams, also called Gram Molecular Mass)

= 16 g

This is the answer

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

b. th3 n4zc4 pl4t3 15 c0nv3rg1ng w1th the s0uth 4m3ric4n pl4t3.