How much work (in J) is involved in a chemical reaction if the volume decreases from 5.20 to 1.13 L against a constant pressure of 0.852 atm ? Express your answer to three significant figures and include the appropriate units.

W = 350.6 J

Explanation:

Given that,

The volume decreases from 5.20 to 1.13 L against a constant pressure of 0.852 atm.

The change in volume = 1.13 L - 5.20 L = -4.07 L

Work done, W = - PΔV

So,

W = 0.852 atm × -4.07 L

= - 3.46 L-atm

or

So, the required work done is 350.6 J.

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms