Given the following liquids and their boiling points, which has the highest vapor pressure at its normal boiling point? a) ethanol, bp = 78°C
b) methanol, bp = 65°C
c) water, bp = 100°C
c) benzene, bp = 80°C
d) The vapor pressure of each of the liquids at its normal boiling point would be the same.

b) methanol, bp = 65°C.

Explanation:

Hello there!

In this case, it turns out necessary for us to firstly remember that the vapor pressure of a liquid is the pressure exerted by the gaseous particles in dynamic equilibrium with the present liquid and thus, the higher the vapor pressure, the weaker the liquid's intermolecular forces because they turn unstable.

In such a way, we can infer that the liquid with the highest vapor pressure, will have the lowest boiling point and therefore, the answer will be b) methanol, bp = 65°C.

Regards!

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890