Question 6 of 25 How much energy does it take to boil 100 mL of water? (Refer to table of
constants for water.)
19
O A. 100 mL *
1 mL
1 mol
х
18.02 g
x 6.03 kJ/mol = 33.5 kJ
1 mol
B. 100 mL X
19
1 mL
х
18.02 g
*(-285.83 kJ)/mol = -1586 kJ
C. 100 mL X
1g
1 mL
х
1 mol
18029
x 4.186 kJ/mol = 23.2 kJ
19
D. 100 mL X
1 mL
Х
1 mol
18.02 g
x 40.65 kJ/mol = 226 kJ

it's 3.2 on edge, i just took the test.

answer is: empirical formula is tl₂o. if we use 100 grams of compound, tha:

m(tl) = 96.2%  · 100 g ÷ 100%.

m(tl) = 96.2 g.

n(tl) = m(tl)  ÷ m(tl). n(tl) = 96.2 g  ÷ 204.4 g/mol.

n(tl) = 0.47 mol. m(o) = 3.77 g. n(o) = m(o)  ÷ m(o). n(o) = 3.77 g  ÷ 16 g/mol. n(ag) = 0.235 mol. n(tl) . n(o) = 0.47 mol : 0.235 mol /0.235. n(tl) . n(o) = 2 : 1.

m(tl₂o) = 204.4 g/mol  · 2 + 16 g/mol = 424.8 g/mol.

m(compound) = 456. 8 g/mol - 424.8 g/mol = 32 g/mol ( 2 oxygens); tl₂o₃.