If you have 9.06 x 10^24 molecules of NaNO3, how many grams do you have of NaNO3

Explanation:

1 mol of anything is 6.02 * 10^23 (in this case molecules)

x mol  has 9.06 * 10^24 molecules of NaNO3

x * 6.02 * 10^23  = 9.06 * 10^24 * 1     Divide by 6.02 * 10^23

x = 9.06 * 10^24/6.02 * 10^23

x = 1.5 * 10

x = 15 mols of NaNO3

1 mol of NaNO3

Na = 23

N = 14

O3 = 48

Total = 85

1 mol of NaNO3 = 85 grams

15 mols = x                              Cross Multiply

x = 15 * 85

x = 1275 grams

Note: these numbers are approximate but they are very close. You have to use your own values from your periodic table to find the mass of NaNO3. Your answer will be very close to 85.

the answer is 1 i believe