C6H12O6 (aq) -> 2 C2H5OH (aq) + 2 CO2 (g) a. How many moles of CO2 are produced when 0.400 mol of C6H12O6 reacts in this
fashion?
b. How many grams of C6H12O6 are needed to form 7.50 g of C2H5OH?
c. How many grams of CO2 form when 7.50 g of C2H5OH are produced?

a. 0.8 moles of CO₂ are produced when 0.400 mol of C₆H₁₂O₆ reacts.

b. 7.5 grams of C₂H₅OH are produced by 14.67 grams of C₆H₁₂O₆.

c. 7.17 grams of CO₂ form when 7.50 g of C₂H₅OH are produced.

Explanation:

The balanced reaction is:

C₆H₁₂O₆  → 2 C₂H₅OH + 2 CO₂

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

The molar mass of each compound is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Then you can apply the following rules of three:

a. If 1 mole of C₆H₁₂O₆ produces 2 moles of CO₂, 0.4 moles of C₆H₁₂O₆ produces how many moles of CO₂?

moles of CO₂= 0.8 moles

0.8 moles of CO₂ are produced when 0.400 mol of C₆H₁₂O₆ reacts.

b. If 92 grams of C₂H₅OH are produced by 180 grams of C₆H₁₂O₆, 7.5 grams of C₂H₅OH are produced by how many mass of C₆H₁₂O₆?

mass of C₆H₁₂O₆= 14.67 grams

7.5 grams of C₂H₅OH are produced by 14.67 grams of C₆H₁₂O₆.

c. If 92 grams of C₂H₅OH are produced along with 88 grams of CO₂, 7.5 grams of C₂H₅OH are produced along with how many mass of CO₂?

mass of CO₂= 7.17 grams

7.17 grams of CO₂ form when 7.50 g of C₂H₅OH are produced.

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