Chemistry, 25.06.2021 01:00 johannah51
0.502 g of an alkali metal sulfate is dissolved in water and excess barium chloride solution,
BaCl2(aq) is added to precipitate all the sulfate ions as barium sulfate, BaSO4(s). The precipitate
is filtered and dried and weighs 0.672 g.
(a) Calculate the amount (in mol) of barium sulfate formed.
(
(b)
Determine the amount (in mol) of the alkali metal sulfate present.
Answers: 2
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0.502 g of an alkali metal sulfate is dissolved in water and excess barium chloride solution,
BaCl2...
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