A solution of the primary standard potassium hydrogen phthalate (KHP), KHC8H4O4 , was prepared by dissolving 0.4877 g of KHP in about 50 mL of water. Titration of the KHP solution with a KOH solution of unknown concentration required 28.49 mL to reach a phenolphthalein end point. What is the concentration of the KOH solution?

0.08382 M

Explanation:

Step 1: Write the balanced neutralization equation

KHC₈H₄O₄ + KOH ⇒ K₂C₈H₄O₄+ H₂O

Step 2: Calculate the moles corresponding to 0.4877 g of KHC₈H₄O₄

The molar mass of KHC₈H₄O₄ is 204.22 g/mol.

0.4877 g × 1 mol/204.22 g = 2.388 × 10⁻³ mol

Step 3: Calculate the moles of KOH that react with 2.388 × 10⁻³ moles of KHC₈H₄O₄

The molar ratio of KHC₈H₄O₄ to KOH is 1:1. The moles of KOH that react are 1/1 × 2.388 × 10⁻³ mol = 2.388 × 10⁻³ mol.

Step 4: Calculate the molar concentration of KOH

2.388 × 10⁻³ moles of KOH are in 28.49 mL of solution.

2.388 × 10⁻³ mol / 0.02849 L = 0.08382 M

a c d and f

just finished the assignment

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.