Write the electronic configuration of calcium and potassium.​

Electronic configuration of Potassium (K)

Atomic number of potassium = 19

Therefore number of electrons = 19

Since, maximum number of electrons in outermost orbit will not be more than 8, thus the 19th electron of potassium atom will reside in 4th.

Thus, electronic configuration of potassium is

given in first pic.

Number of orbit in potassium = 4

Electronic configuration of Calcium (Ca)

Atomic number of calcium = 20

Therefore number of electrons = 20

Thus, electronic configuration of calcium is given in sec pic.

Number of orbit in calcium = 4

Explanation:

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Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.