Se trata 50 g de aluminio que posee 10% de impurezas con suficiente cantidad de ácido sulfúrico ¿qué peso de sulfato de aluminio se obtiene si el porcentaje de rendimiento fue de 70%? P. A. (uma): Al: 27, S = 32, O = 16

Respuesta:

199.5 g

Explicación:

Paso 1: Escribir la reacción balanceada

2 Al + 3 H₂SO₄ ⇒ Al₂(SO₄)₃ + 3 H₂

Paso 2: Calcular la masa pura de 50 g  de Al

Aluminio tiene 10% de impurezas, es decir, 10% de 50 g = 5 g. Luego, tiene 50 g - 5 g = 45 g de Al puro.

Paso 3: Calcular la masa teórica de Al₂(SO₄)₃ obtenida a partir de 45 g de Al

La relación de masas de Al₂(SO₄)₃ a Al es 342:54.

45 g Al × 342 g Al₂(SO₄)₃/54 g Al = 285 g Al₂(SO₄)₃

Paso 4: Calcular la masa real de Al₂(SO₄)₃ obtenida

El rendimiento de la reacción es de 70%.

285 g × 70% = 199.5 g

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

e

smooth muscle is composed of involuntary muscles found within the walls of organs and structures such as the esophagus, stomach, intestines, and blood vessels. those muscles push materials like food or blood through organs. unlike skeletal muscle, smooth muscle can never be under your control.