Need help asap - There is an error in the rate-determining step of the following proposed mechanism. Slow step: CH3(g) + Cl2(g) → CH3(g) + HCl(g) and the rate rule is k1 = [CH4][Cl2]
Fast step: CH3(g) + Cl2(g) → CH3Cl(g) + Cl–(g) and the rate rule is k2 = [CH4][Cl2]
Overall : CH4(g) + 2Cl2(g) → CH3Cl(g) + HCl(g) + Cl–(g)

Which shows the correct rate-determining step for the mechanism?

CH4(g) + 2Cl(g) → CH3Cl(g) + HCl(g) + Cl–(g)
CH4(g) + Cl2(g) → CH3(g) + HCl(g) and the rate rule is k1 = [CH4][Cl2]
CH4(g) + Cl2(g) → CH3Cl(g) + Cl–(g) and the rate rule is k2 = [CH4][Cl2]
CH3(g) + 2Cl2(g) → CH3Cl(g) + Cl–(g) and the rate rule is k2 = [CH4][Cl2]

Explanation:

Need help asap - There is an error in the rate-determining step of the following proposed mechanism.

Slow step: CH3(g) + Cl2(g) → CH3(g) + HCl(g) and the rate rule is k1 = [CH4][Cl2]

Fast step: CH3(g) + Cl2(g) → CH3Cl(g) + Cl–(g) and the rate rule is k2 = [CH4][Cl2]

Overall : CH4(g) + 2Cl2(g) → CH3Cl(g) + HCl(g) + Cl–(g)

Which shows the correct rate-determining step for the mechanism?

CH4(g) + 2Cl(g) → CH3Cl(g) + HCl(g) + Cl–(g)

CH4(g) + Cl2(g) → CH3(g) + HCl(g) and the rate rule is k1 = [CH4][Cl2]

CH4(g) + Cl2(g) → CH3Cl(g) + Cl–(g) and the rate rule is k2 = [CH4][Cl2]

CH3(g) + 2Cl2(g) → CH3Cl(g) + Cl–(g) and the rate rule is k2 = [CH4][Cl2]

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).