Calculate [H3O+] and [OH−] for each of the following solutions at 25 ∘C given the pH.
pH= 11.22

The value of is M and is .

Explanation:

pH is the negative logarithm of concentration of hydrogen ion.

It is given that pH is 11.22. So, the value of concentration of hydrogen ions is calculated as follows.

M

Let the value is considered as equal to 0. Hence, the relation between pH and pOH value is as follows.

pH + pOH = 14

0 + pOH = 14

pOH = 14

Now, pOH is the negative logarithm of concentration of hydroxide ions.

Hence, is calculated as follows.

Thus, we can conclude that the value of is M and is .

i believe the answer is a.

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.